Redox (shorthand for reduction-oxidation reaction) describes all chemical reactions in which atoms have their oxidation number (oxidation state) changed. This can be either a simple redox process such as the oxidation of carbon to yield carbon dioxide or the reduction of carbon by hydrogen to yield methane (CH4), or it can be a complex process such as the oxidation of sugar in the human body through a series of very complex electron transfer processes.

The term redox comes from the two concepts of reduction and oxidation. It can be explained in simple terms:

  • Oxidation describes the loss of electrons or an increase in oxidation state by a molecule, atom or ion.
  • Reduction describes the gain of electrons or a decrease in oxidation state by a molecule, atom or ion.

Though sufficient for many purposes, these descriptions are not precisely correct. Oxidation and reduction properly refer to a change in oxidation number — the actual transfer of electrons may never occur. Thus, oxidation is better defined as an increase in oxidation number, and reduction as a decrease in oxidation number. In practice, the transfer of electrons will always cause a change in oxidation number, but there are many reactions that are classed as "redox" even though no electron transfer occurs (such as those involving covalent bonds).

Non-redox reactions, which do not involve changes in formal charge, are known as metathesis reactions.

The two parts of a redox reaction Rusting iron A bonfire. Combustion consists of redox reactions involving free radicals.

From Wikipedia under the GNU Free Documentation License
Wed Oct 7 02:34:22 2009

I need help with this reaction to identify whether they are reduction, oxidation, or neither ?
Q. a) V2O5 (aq)---> V (s) b) P4 (s) ---> H3PO4 (aq) c) CrO3 (s) ---> H2CrO4 (aq) d) CH3CH2OH (aq) ---> CO2 (g) for a i put reduction for b i put neither for c i didnt know for d i put oxidation im i right or not? and if possible what is being reduced or oxidized
Asked by joe - Tue Oct 21 22:11:25 2008 - - 2 Answers - 0 Comments

A. 1. is reduction V is reduced from +5 to 0 2. is oxidation. P4 starts at 0 and P in H3PO4 becomes 5 3.neither in both sides the H is +1 O is -2 and Cr is +6 4.you are right its oxidation C is oxidized from -2 to +4
Answered by effiligious313 - Tue Oct 21 22:19:20 2008

Narrate the process of energy consumption and redox (reduction/ oxidation) of the Calvin Cycle.?
Q. please help!
Asked by sakuramiko12 - Tue Feb 10 08:16:43 2009 - - 1 Answers - 0 Comments

A. Calvin Cycle The second stage of photosynthesis, which takes place in the stroma of the chloroplast, can occur without the presence of sunlight. In this stage, known as the Calvin Cycle, carbon molecules from CO2 are fixed into glucose (C6H12O2). The reactions of the Calvin Cycle is as follows: 1. A five-carbon sugar molecule called ribulose bisphosphate, or RuBP, is the acceptor that binds CO2 dissolved in the stroma. This process, called CO2 fixation, is catalyzed by the enzyme RuBP carboxylase, forming an unstable six-carbon molecule. This molecule quickly breaks down to give two molecules of the three-carbon 3-phosphoglycerate (3PG), also called phosphoglyceric acid (PGA). 2. The two 3PG molecules are converted into… [cont.]
Answered by Peter S - Tue Feb 10 08:45:58 2009

Half Reaction Question?
Q. MnO4^- (aq) + IO3^- --> MnO2(s) + IO4^- (aq) In basic Sol. 1 H2O to balance H atoms and 2OH- to Balance O atoms..correct? I have this much, and I believe the first reduction/oxidation part
Asked by probably confused! - Thu Sep 11 01:02:18 2008 - - 1 Answers - 0 Comments

A. MnO4^- (aq) + IO3^- --> MnO2(s) + IO4^- (aq) Oxidation numbers MnO4-: Mn = +7 => MnO2: Mn = +4 => reduction IO3- = 1 = +5 => IO4-: I = +7 => oxidation Ox: IO3- --> IO4- IO3- + H2O --> IO4- + 2H+ IO3- + H2O + 2OH- --> IO4- + 2H2O (from the 2H+ and the 2OH-) IO3- + 2OH- --> IO4- + H2O + 3e- I think you're correct because that's exactly what I have. You should be able to write the reduction at the cathode now. Just remember to balance oxygen by adding water, and in basic solution add the hydronium ion (H+) to balance hydrogen. Then add OH- because its basic. The H+ and the OH- will form water.
Answered by JohnDx5454 - Thu Sep 11 01:17:40 2008

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